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<div class="moz-cite-prefix">Hi Paul,<br>
Try : GROUP BY biblionumber HAVING count(biblionumber)>1<br>
That way, it will work even for biblios without ccode.<br>
François<br>
<br>
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<div class="sig_content"> <span class="nom">François
Charbonnier,</span><br>
<span class="tagline small">Chef de produits</span><br>
<p class="desc small"> Tél. : (888) 604-2627<br>
<a href="mailto:francois.charbonnier@inLibro.com">francois.charbonnier@inLibro.com</a>
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<div class="sig_footer"> <span class="in">in</span><span
class="libro">Libro</span> <span class="tagline small">|
pour esprit libre |</span> <a class="small"
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Le 2014-01-20 16:06, Paul A a écrit :<br>
</div>
<blockquote cite="mid:5.2.1.1.2.20140120155406.04c87a70@stormy.ca"
type="cite">I'm going round in circles for what I thought would be
easy, and will kick myself later.
<br>
<br>
Trying to write a "report" that will give me all biblios with more
than 1 item:
<br>
<br>
SELECT
<br>
biblionumber, CONCAT('<a
href=\"/cgi-bin/koha/catalogue/detail.pl?biblionumber=',biblionumber,'\">',title,'</a>')
AS Title, author AS Author
<br>
FROM biblio b
<br>
LEFT JOIN items i USING (biblionumber)
<br>
GROUP BY i.ccode
<br>
HAVING COUNT(i.itemnumber)>1;
<br>
<br>
works syntactically, but certainly does not give me the right
answers -- it produces biblios with 0, 1, 2, etc items, and only
83 total lines when I know that there are thousands...
<br>
<br>
Logic seems to have deserted me. Help please?
<br>
<br>
As a bonus, I'd appreciate how to add the items.ccode into the
report. Adding SELECT ccode FROM items either before or after the
JOIN fails.
<br>
<br>
Thanks and br -- Paul
<br>
<br>
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