Paul,

By the way, I forgot to mention you could add ccode this way :

SELECT biblio.biblionumber, CONCAT('<a href=\"/cgi-bin/koha/catalogue/detail.pl?biblionumber=',biblionumber,'\">',title,'</a>') AS Title, biblio.author, GROUP_CONCAT(items.ccode SEPARATOR ', ') as ccode
FROM biblio LEFT JOIN items USING(biblionumber)
GROUP BY biblionumber
HAVING COUNT(biblionumber)>1;

Hope it helps!

François

François Charbonnier,
Chef de produits

Tél.  : (888) 604-2627
francois.charbonnier@inLibro.com

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Le 2014-01-20 16:06, Paul A a écrit :
I'm going round in circles for what I thought would be easy, and will kick myself later.

Trying to write a "report" that will give me all biblios with more than 1 item:

SELECT
biblionumber, CONCAT('<a href=\"/cgi-bin/koha/catalogue/detail.pl?biblionumber=',biblionumber,'\">',title,'</a>') AS Title, author AS Author
FROM biblio b
LEFT JOIN items i USING (biblionumber)
GROUP BY i.ccode
HAVING COUNT(i.itemnumber)>1;

works syntactically, but certainly does not give me the right answers -- it produces biblios with 0, 1, 2, etc items, and only 83 total lines when I know that there are thousands...

Logic seems to have deserted me. Help please?

As a bonus, I'd appreciate how to add the items.ccode into the report. Adding SELECT ccode FROM items either before or after the JOIN fails.

Thanks and br -- Paul

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